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E7AF80E7B484 E9A39FE8B2BB

📅 November 12, 2026📖 Verified Publication
We need answer user's request. Need output raw HTML only no markdown. Need produce SEO article about "E7AF80E7B484 E9A39FE8B2BB". Need understand what these strings are. Likely UTF-8 encoded Chinese? Let's decode. E7AF80 E7B484 = 微信? Let's check: 微 U+5FAE UTF-8 E5 BE AE? Wait E7 AF 80 is 微? Let's calculate: 微 Unicode 5FAE. UTF-8: E5 BE AE. E7 AF 80 corresponds U+7FA0? Actually E7 AF 80 -> 0x7FA0 = 微? Let's see CJK: 0x7FA0 maybe 微? I know 微信: 微 = E5 BE AE? 信 = E4 BF A1. But E7 AF 80 E7 B4 84: 0x7FA0 and 0x7BB4. 0x7FA0 = 微? Let's verify common: 微信 UTF-8 is E5 BE AE E4 BF A1. So not. E9A39F E8B2BB: 0x9F9F? E9 A3 9F = U+9F9F = 群? E8 B2 BB = U+82BB = 聊? So second is 群聊. First maybe 微信? Wait E7AF80 E7B484 = 0x7FA0 0x7BB4. 0x7FA0 = 微? Let's recall: 微 code point maybe 0x5FAE, not 0x7FA0. 0x7FA0 is 微? No, 0x7FA0 is 微? Let's think: Chinese characters in 0x7xxx. 0x7FA0 could be 微? Actually 0x5FAE is 微? Let's confirm: 微 in Unicode is U+5FAE. Yes. So E5 BE AE. E7 AF 80 is U+7FA0, which is 微? Maybe not. U+7FA0 is 微? Let's search memory: 0x7FA0 maybe 微? Hmm. Maybe the strings are percent-encoded? E7AF80 E7B484 E9A39F E8B2BB without %? If URL encoded: %E7%AF%80%E7%B4%84%E9%A3%9F%E8%B2%BB. Decode: 微? Let's decode mentally: %E7%AF%80 = U+7FA0. What char? Maybe 微? Let's use known: 微信 is %E5%BE%AE%E4%BF%A1. So not. Could be GBK? E7AF80 E7B484 in GBK? Need decode? GBK E7AF maybe? Let's think: GBK bytes: E7 AF = 微? In GB2312/GBK, 微 is D2 C2? Not. Maybe these are hex for UTF-16? E7AF 80E7 B484 E9A3 9FE8 B2BB? Could be code points? 0xE7AF? No. Maybe it's a topic title encoded in UTF-8 hex: "E7AF80E7B484 E9A39FE8B2BB" likely "微信 群聊"? Let's check if 微信 in some encoding: Big5? 微 in Big5 = A6 A9? 信 = A4 C6. Not. Could be UTF-8 for "微群"? E7 AF 80 = 微? Let's verify: Unicode 微 U+5FAE, but maybe I'm wrong? Let's use formula: UTF-8 3 bytes E7 AF 80: code point = ((0xE7 & 0x0F)<<12) | ((0xAF & 0x3F)<<6) | (0x80 & 0x3F) = 7<<12=0x7000; AF&3F=2F<<6=0x7C0; 80&3F=0; total 0x77C0? Wait 0xAF = 10101111, &0x3F=00101111=0x2F, <<6=0x7C0. 0x7000+0x7C0=0x77C0. So U+77C0, not 0x7FA0. I miscomputed. U+77C0 is 微? Let's see: 微 maybe U+5FAE? But U+77C0 could be 微? Actually 0x77C0 is 微? Let's recall: 0x77C0 maybe 微? Chinese char 微: in Unicode maybe 0x5FAE? I thought. Let's verify via known: 微 in pinyin wei. U+5FAE? Could be. U+77C0 maybe 微? Let's check: 0x77C0 is 微? There is char 微 at 0x5FAE? Let's recall common CJK: 0x4e2d 中, 0x56fd 国, 0x5fae 微? Maybe. But U+77C0 maybe 微? Let's calculate for 信: UTF-8 E4 BF A1: code = 4<<12=0x4000, 3F<<6=0xFC0, 1 = 0x4FC1. U+4FC1 = 信? I thought 信 is U+4FE1? Wait 信 maybe U+4FE1. So maybe my memory off. Let's decode known: 中 U+4E2D UTF-8 E4 B8 AD. 国 U+56FD UTF-8 E5 9B BD. 信? Could be U+4FE1 UTF-8 E4 BF A1? E4 BF A1 -> 0x4FC1? Actually E4 = 11100100, bits 0100; BF=10111111 bits 111111; A1=10100001 bits 100001. Combine 0100 111111 100001 = 0x4FA1? Wait 4<<12 = 0x4000, 0x3F=63, BF & 3F = 0x3F (63) <<6=0xFC0, A1&3F=0x01, total 0x4FC1? 0x4000+0xFC0+1=0x4FC1. But if 信 is U+4FE1, UTF-8 would E4 BF A1? Let's compute U+4FE1: binary 0100 111111 100001? 0x4FE1 = 0100 111111 100001? 0x4FE1 = 0100 111111 100001 yes. UTF-8: 1110 0100, 10111111, 10100001 = E4 BF A1. So U+4FE1. My formula: 0x4 <<12 = 0x4000; 0xFE? Wait code point 0x4FE1 split 16 bits: 0100 (4), 111111 (3F), 100001 (1). 0x4000 + 0xFC0 + 1 = 0x4FC1? But 0x4FE1 = 0x4000 + 0xFE1? 0xFE1 = 0xFC0 + 0x21? Hmm split wrong. 16-bit split: first 4 bits, next 6, last 6. 0x4FE1 = binary 0100 111111 100001? Let's write 16 bits: 0x4FE1 = 0100 111111 100001? Count: 0x4FE1 = 0100 111111 100001 indeed? 0x4 = 0100, 0xF=1111, 0xE=1110, 0x1=0001 => 0100 1111 1110 0001. Group 4+6+6: 0100 | 111111 | 100001. Yes last 6 bits 100001 = 0x21, not 0x01. I misread A1 bits: 10100001 & 3F = 100001 = 0x21. So total 0x4000+0xFC0+0x21=0x4FE1. Good. For E7 AF 80: 0xE7 = 11100111, lower 4 = 0111 = 7. 0xAF = 10101